Sunday 11 October 2015

Power diode single phase half wave rectifier .


Lab Title:  Power diode single phase half wave rectifier .
Objective: To become familiar with the process of rectification using power diodes under different load .
Apparatus:
        i.            Power diode
     ii.            Voltage Source
   iii.            Resisters (220 ohm)
   iv.            Inductor (0.8H)
     v.            Voltmeters and Ammeters
   vi.            Connection cables
vii.             LV-DEC software for analysis.

Introduction:
The process of converting alternating voltage to direct voltage at the output is known as rectification.In this practical we do the half wave rectification using power diode under different types of load.During positive half cycle diode will be on and during next negative half cycle diodeFirst we do this process through resistive load and then by using both resistive and inductive load.         

Procedure:
·        Install the power supply, the resistive loads, the DC voltmeter/ammeter and the power diodes module in the workstation.
·        Make sure that the main power switch of the power supply is set to 0. Set the voltage control knob to 0. Connect the power supply to a three-phase wall receptacle.
·        Plug the Power supply line cord into a wall receptacle.  Set the rocker switch of the power supply to the 1(on position).
·        Make sure that the toggle switches on the resistive Load are all set to the 0.
·        In the last observe the three phase waveform, and measure the output parameters.
Precautions:
1.     Make sure that the main power switch of the power supply is set to the 0 (OFF) Position.
2.     Make the circuit neat and clean.
3.     Make sure that the toggle switches on the resistive load are all set to the 0 (open) positions.
4.     Take the reading very carefully.
Circuit diagram: (Resistive Load)

Output Waveforms in case of Resistive Load :-


Circuit diagram: (Inductive Load)
Output Waveforms in case of Inductive Load :-




Load
Output voltage(V)
Output current(A)
Output power(W)
Resistive
149.26
0.23
34.32
Inductive
149.63
0.67
100.25

Conclusion:

In this lab,we see that half wave rectification under inductive load produces more power than resistive load.This is because inductor will oppose the change in current by changing its polarity and efficiency will be increase.

No comments:

Post a Comment